Organization of Computer Systems:
§ 2: ISA, Machine Language, and Number Systems

Instructor: M.S. Schmalz

Reading Assignments and Exercises

This section is organized as follows:

Information contained herein was compiled from a variety of text- and Web-based sources, is intended as a teaching aid only (to be used in conjunction with the required text, and is not to be used for any commercial purpose. Particular thanks is given to Dr. Enrique Mafla for his permission to use selected illustrations from his course notes in these Web pages.

Reading Assignments and Exercises

2.1. ISA and Machine Language

Reading Assignments and Exercises

The instruction set architecture (ISA) is a protocol that defines how a computing machine appears to a machine language programmer or compiler. The ISA describes the (1) memory model, (2) instruction format, types and modes, and (3) operand registers, types, and data addressing. Instruction types include arithmetic, logical, data transfer, and flow control. Instruction modes include kernel and user instructions.

ISAs are specified in formal definition documents, for example, for the V9 SPARC machine and Java Virtual Machine.

2.1.1. Hierarchical View

As discussed previously, computing languages are translated from source code to assembly language to machine language, as illustrated notionally in Figure 2.1.



Figure 2.1. Example of computing language translation, adapted from [Maf01]

The implementation of the ISA in hardware is couched in terms of the fetch-decode-execute cycle illustrated in Figure 2.2. In the fetch step, operands are retrieved from memory. The decode step puts the operands into a format that the ALU can manipulate. The execute cycle performs the selected operation within the ALU. Control facilitates orderly routing of data, including I/O to the ALU's external environment (e.g., peripheral devices such as disk or keyboard).



Figure 2.2. Basic ISA cycle, where fetch gets operands from memory, decode translates the operands into a format the ALU can accept, and execute performs an ALU operation on the decoded operands - adapted from [Maf01]

2.1.2. Machine Language

Machne language instructions are of four types: Arithmetic, Logical, Data transfer, and Branches (also called flow control), as follows:

The MIPS instruction format uses the KISS principle (keep it simple and stupid). As we say more formally:

Design Principle #1: Simplicity favors regularity.

This means that the MIPS instruction format is the same for all instructions. Each instruction begins with an opcode that tells the machine what to do, followed by one to three operand symbols.



Figure 2.3. MIPS instruction - simple addition example, adapted from [Maf01]. These instructions are symbolic examples of what MIPS actually understands.

As an example of the symbolic notation used in Figure 2.3, consider the following equation, expressed in C language format, accompanied by its translation into MIPS assembly language:

Symbolic names make assembly language code more readable. In the preceding example, note that we have temporary variables t0 and t1, as well as input/result variables f, g, h, i, and j. In MIPS, we also have eight temporary registers labelled $t0 through $t7 and nine s-registers labelled $s0 through $s8. The s-registers can be thought of as containing data that are typically stored in C variables. Thus, in MIPS, operands cannot be any variable, and there are only thirty-two 32-bit registers (a memory location that holds 32 bits). This conforms to the following observation:

Design Principle #2: Smaller is faster.
Thus, in proper MIPS code, the preceding example would become:

2.1.3. MIPS Memory

Memory contains instructions and data specific to a given program. Instructions are fetched automatically by control, while data is transferred explicitly between the memory and processor. Figure 2.4 shows an example of memory operations in MIPS using the lw (load word) and sw (store word) instructions.



Figure 2.4. Use of lw and sw instructions to transfer data between memory and processor, adapted from [Maf01].

Here, data is organized in linear memory as a stream of bits. Each byte is comprised of eight contiguous bits, and each word is comprised of four contiguous bytes.

Data stored in memory is referenced using an address, which is an identifier that points to a byte in memory. Addresses in MIPS range from 0 (which points to data in the part of memory denoted as M[0]) up to 4,294,967,292 (referenced data is written as M[232]). Thus, all addresses are 32 bits long, so 230 32-bit (four-byte) words are stored in MIPS memory.

Only load/store instructions can access data in memory. Since each word has length 4 bytes, the addresses referenced by these instructions must be aligned, that is, all 32-bit words start at addresses 0, 4, ..., 4n. Because of differences between computer manufacturers and the way different machines address memory, the MIPS address formats have two types of encoding: big endian and little endian, as shown in Figure 2.5. Here, a decimal (base-10) address of 3,101 is broken down into a hexadecimal (base-16) address of (00 00 0c 1d)16. Big endian stores the big part (00) at the top or beginning of the address, and little endian is the reverse of big endian (stores (1d) at the beginning of the address).



Figure 2.5. Example of big and little endian encoding, adapted from [Maf01].

There are other interesting things you can do with memory addressing, such as offsets. For example, suppose you wanted to add a number in memory location A[2] and put the result in A[0]. We know that A[2] has the larger address, and this can be loaded using an offset of 8, as shown in Figure 2.6. Here, the register $s1 represents the base address, and the contents of the variable h are stored in register $s2.



Figure 2.6. Example of memory offsets, adapted from [Maf01]. The circled operands show how an address offset is represented in a MIPS instruction.

2.2. Instruction Representation

Reading Assignments and Exercises

Computer instructions are based on three number systems: decimal, binary, and hexadecimal. Salient features of these systems include:

The basic operating concept of modern computers is the stored program, by which programs can be loaded into various partitions (blocks) of memory, then retrieved and loaded into the processor. In the preceding section, we noted that the CPU control does this automatically. In hardware, this is typically accomplished by a device called an instruction sequencer.

2.2.1. Machine Language Instruction Format

In machine language, all instructions have the same length. In MIPS, this design compromise produces instructions that are 32 bits long. The governing principle follows:

Design Principle #3: Good design demands good compromises.

MIPS instructions have three different formats:

  1. R format - Arithmetic instructions

  2. I format - Branch, transfer, and immediate instructions

  3. J format - Jump instructions

These formats are further explained in Figure 2.7. Note that jump instructions merely transfer control (execution) to the specified memory address. As a result, J-format instructions are not very interesting, so we will concentrate the remainder of discussion in this section on R- and I-format instructions.



Figure 2.7. MIPS instruction format, adapted from [Maf01].

Example 1. Consider an example of an R-format instruction add $t0 $s1 $s2, which means that we add two numbers stored in C registers 1 and 2 ($s1 and $s2), then put the result in temporary register 0 ($t0). Here, $t0 has the address 8, and the C-registers have the addresses 17 and 18. The "$" sign means contents-of. For example $18 means contents of register whose address is 18. Also, note that the order of the operands in the machine language instruction (ones and zeros) is different than in the assembly-language version.

Important Note. MIPS has several register conventions that you should know, which are summarized in the following table. These conventions will be observed as we progress toward more involved MIPS programs.

Table 2.1. MIPS Register Conventions, adapted from [Maf01]

Example 2. A slightly different example of an R-format instruction involves subtraction - sub $t1 $s1 $s2, which means that we add two numbers stored in C registers 1 and 2 ($s1 and $s2), then put the result in temporary register 1 ($t1). Here, $t1 has the address 9, and the C-registers have the addresses 17 and 18, as before. Note that the funct code for subtraction (34) is different from that for addition (32), and that there is no shifting.

Example 3. Consider an example of an I-format instruction that involves loading a word - lw $t0 52($s3) , which means that we load a word into register $t0, which has address 8, by fetching the data from memory location $s3, which has address 19, with an offset of 52.

Example 4. Another example of an I-format instruction involves storing a word - sw $t0 52($s3), which is the opposite of the instruction in Example 3. Note that the opcode for store (43) is different from that for load (35), and that the addresses are kept the same, for simplicity.

We next assemble these concepts together to show how an instruction is translated from a high-level language to assembly language, and thence to machine language.

Example 5. Given the high-level statement A[300] = h + A[300]; the following translation sequence holds:

Note that A[300] is stored in memory with an offset of 1200. This is due to the 32-bit word length (four bytes) that we discussed in Section 2.1. Since memory is structured as a linear array of bytes, to obtain the correct byte offset to maintain word alignment, we need to multiply the memory location in source code by the word length (e.g., byte offset 1200 = word 300 · 4 bytes/word).

2.2.3. Special Cases

Thus far, we have overviewed the basic add, sub, load, and store instructions. However, MIPS has several special cases of these instructions, which are designed to make programs run much faster. We consider these special cases, as follows.

2.2.3.1. Addition of Constants. By analyzing large bodies of source code (also called corpi, the plural of corpus), the developers of MIPS were able to determine that small constants are used frequently and comprise approximately 50 percent of operands. For example, A = A + 5; and C = D - 1; respectively are common types of increment or decrement statements. In general, if an event occurs 50 percent or more of the time, then it is called the common case, and the following principle applies:

Design Principle #4: Make the common case fast.

As a result of this concept, MIPS puts typical constants in memory and loads them into special hardwired registers (e.g., $0).

Example 6. Consider the following add immediate instruction for addition of a register and a constant (I-format):

Here, the contents of C-register $s7 are added to the constant 4 and put into the temporary register $t0. The constant 4 is represented at the right-hand part of the instruction as a two-byte (16-bit) value. The opcode for addi is 8, which is different from the add instruction's opcode (per Example 1, above). As in our previous examples, $t0 has the address 7, and it is readily determined that $s7 has the address 23.

2.2.3.2. Overflow. Compilers have limited precision (usually 32 bits). If a result of an addition or multiplication is a number that requires a binary representation larger than 32 bits, then we have a problem. We call this situation register overflow, because the number to be loaded into the register is larger (i.e., has more bits) than the register can accomodate.

Some high-level languages (e.g., Ada and certain Fortran compilers) detect overflow, while others (e.g., C) do not. MIPS provides two types of arithmetic instructions:

  1. add, sub, addi cause overflow; while

  2. addu, subu, addiu do not cause overflow.

MIPS C compilers produce addu, subu, and addiu instructions by default, thereby extending the ANSI standard C language specification.

2.2.3.3. Logical Operations. In MIPS, a logical constant is expressed as a vector of 32 ones and zeroes, not as an integer number. This leads to the practice of bitwise logical operations that operate in parallel upon a vector of Boolean numbers, for example:

(0010 0001 0100) = (0010 0001 0110) and (1010 0011 0101)

In MIPS instructions and and or, the operands are registers, and the R-format instruction is used (similar to the add instruction in Example 1, above). In contrast, MIPS instructions andi and ori have operands that are immediates, and the I-format instruction is used. An example of the I-format logical instruction follows.

Example 7. Consider the following andi instruction for and-ing a register and a logical constant (a Boolean number):

andi $t0, $t0, 0xFFF

This instruction has several interesting characteristics. The first operand is stored in register t0, and is anded with a logical constant specified in hexadecimal as 0xFFF. This representation means fill the word with zeroes until you get to the last three digits, which are f, f, and f. Since F16 = (1111)2, we have the second operand shown above. When the logical and operation is applied bitwise to these operands, the result is shown below the line. Note that the word 0xFFF is called a mask because anding causes the result to be zero (one) in those bit positions where the mask has the value of zero (resp. one).

2.2.3.4. Shift Instructions. In order to move the contents of a register to the left or right efficiently, MIPS has a dedicated shift capability that is controlled by the following shift instructions:

Example 8. Assume that the R-format instruction srl $t0, $s1, 8 is applied as shown below. The shift amount, represented as shamt, is the number of bits to shift the operand $s1 to yield the result in $t0.

Since the instruction is R-format, note that the opcode is modified by the funct descriptor (000010) that occupies the last six bits of the instruction. Shift instructions are used for a wide variety of operations, including the pencil-and-paper algorithm for multiplication of binary numbers.

2.2.3.5. Multiplication and Division. We will discuss multiplication and division in MIPS in detail in Section 3.3. For now, consider the following information as useful in the context of the MIPS instruction format.

Multiplication and division of two N-bit numbers produce a result that can be as large as 2N significant digits (i.e., 2N bits). As a result, MIPS uses two registers, called hi and lo, to store the upper and lower parts of the product (for multiplication) as well as the remainder and quotient (for division).

Example 9. Assume that mult $s0, $s1 produces the product of registers s0 and s1. In order to get the high and low part of the product into 32-bit registers s2 and s3, so the product can be further manipulated, the following instructions would be used: 

        mfhi $s2
        mflo $s3

2.2.4. Assembly vs. Machine Language

Assembly language is a convenient symbolic notation that is much easier to write and understand than a stream of ones and zeroes (machine language). In MIPS assembly language notation, the destination (result) is first in the operand list. This is generally the convention for the vast majority of assembly languages.

In contrast, machine language is the underlying reality of program representation (bit stream) that is fed into the processor. Each machine language instruction has the destination (result) register in the last position.

Although assembly language can provide convenient pseudo-instructions, it is the machine language instruction that is actually executed.

Important Note: When counting instructions to calculate the instruction count (IC) of a given program, count machine language instructions, since they are the only instructions executed. If you count assembly language instructions, then you will have an IC that is misleadingly small, since one assembly language instruction can be translated to several machine language instructions.

This concludes our overview of MIPS instruction format. We next examine how the MIPS architecture supports decision instructions and procedures.

2.3. Decision Instructions and Procedure Support

Reading Assignments and Exercises

Decision instructions express control flow in computer program execution. Important types of decision instructions include:

2.3.1. Conditional Branches

Conditional branch instructions in MIPS have the following format:

opcode register1, register2, destination_address

where opcode is either beq (branch on equality) or bne (branch on inequality). These instructions compare the contents of register1 and register2 to determine if they are equal. If equal (not equal), then beq (bne) transfers control to destination_address. Otherwise, control is transferred to the next instruction in the machine language instruction sequence.

MIPS decision instructions have the machine language format described in Section 2.2 of these notes. An example follows.

Example 1. Suppose we have the following MIPS assembly language instruction:

beq $s3, $s4, 20

The registers have addresses 19 and 20, the opcode is 4 (for beq) and the destination address is 5 (the 20th byte is in the fifth word, since each word is 4 bytes long). Thus, we have:

In MIPS, there is no need to calculate the addresses for branches - the assembler does this for you, as shown in the following example.

Example 2. Suppose we have the following high-level language code: 

       if (i == j) go to L1;
       f = g + h;
  L1:  f = f - i;

where register assignments are: 

    f => $s0 , g => $s1 , h => $s2
    i => $s3 , j => $s4

The corresponding MIPS assembly code is as follows:

2.3.2. Jump Instruction

The MIPS jump instruction functions like the go to instruction in C, that is, control is transferred to a specific destination address in memory. The instruction format is either of the following two forms: 

      j  label
      j  destination_address

where label is shown as "L1" in Example 2 of Section 2.3.1. Here, label is a string and destination_address is a numberical constant within the range of permissible MIPS address values.

Example 3. Suppose we have the following assembly language code: 

      j 1024

The corresponding MIPS machine language representation follows:

As before, the machine language address representation is calculated as 256 = 1024 bytes / 4 bytes/word.

beq $s3, $s4, 20

2.3.3. If Statements

The purpose of an if statement is to provide conditional transfer of control to one or more blocks of statements, one of which is executed when its corresponding condition coded in the if-statement is satisfied. The if-statement can be implemented using the infamous go to statement, as shown in Figure 2.8.



Figure 2.8. Implementation of an if statement in terms of high-level language using the go to statement, adapted from [Maf01].

Example 4. Suppose we want to translate an if-statement from high-level language into MIPS assembly language. According to the method of Figure 2.8, this would be done as follows:

Note: There is a mistake in this figure - the third MIPS statement (j Fin) should read (j False).

2.3.4. Loop Statements

Loop statements include for, while, and do-while control structures.

2.3.4.1. For-loops. A simple iterative structure is the for-loop, which has the following form: 

     for index = base to target by increment
         ...statements to be executed...
     endfor

where index is a counter to be incremented, base (target) is the starting (ending) value for index, and increment is the step value that is added to index each time control passes through the loop. The for-loop is implemented in terms of the go to statement, as follows: 

          index = base 
   Loop:  ...statements to be executed...
          index = index + increment
          if index is greater than or equal to target goto Fin
          else goto Loop
   Fin:

This can be translated to MIPS assembly language, as shown in the following example.

Example 5. Consider the translation of a loop from the preceding high-level language go-to format into MIPS assembly language, as shown in Figure 2.9.



Figure 2.9. Implementation of a loop statement in terms of MIPS assembly language using the go to statement, with register assignments shown on the left - adapted from [Maf01].

Note that the first three assembly instructions set the value of $t1, which holds the address of the memory element A[i]. The register $t0 stores the value A[i] that is in the i-th memory element, while g is the accumulator variable and i represents the loop index. The last MIPS statement implements the loopback which branches to the label Loop if the index i is less than the value h, which is stores in register $s2.

2.3.4.2. While-loops. A variation of the for-loop is the while-loop, which makes the execution of statements within the body of the loop contingent on the satisfaction of a condition. The while-loop has the following form in high-level language: 

     while (condition)
       ...statements to be executed... ;

where condition is a logical predicate that evaluates to true or false. In each iteration of the loop, the while-loop first checks to see if condition is true. If condition evaluates to false, then the loop exits. Otherwise, the statements in the body of the loop are executed.

Example 6. Consider the translation of a while-loop from the high-level language format to MIPS assembly language, as shown in Figure 2.10.

Here, the first three MIPS statements establish the loop index, which in turn establishes the address of the memory element save[i]. (Note that "save" is being used instead of "M", to accustom you to the use of different variables to describe stored data.) In the fourth MIPS statement, the condition (save[i] != k) is checked to see if it is time to exit the loop by transferring control to the label Exit. This is done using the bne operation. The sixth statement comprises the body of the loop, where the variable i is incremented by the amount j. The final MIPS statement implements loopback.



Figure 2.10. Implementation of a while statement in terms of MIPS assembly language using the jump statement, with register assignments shown in bold type at the top of the lower box, adapted from [Maf01].

Analysis. It is useful to examine the code in Figure 2.10. A cursory technique is to calculate the number N of MIPS assembly instructions executed if save[i + m * j] does not equal k (for m = 10), or if save[i+m*j] = k (for m between 0 and 9). In that case, there are 7 instructions executed per iteration of the loop (i = 0 to i = 9), plus five instructions executed when control exits the loop (because branch to Exit is the fifth MIPS instruction). Thus, N = 10(7) + 5 = 75 instructions.

Note: This technique of cursory analysis is acceptable in this case, because there happens to be a one-to-one correspondence between assembly and machine language instructions. However, if there were more machine language instructions than assembly instructions, then we would have to modify the number 7 in the equation N \ 10(7) + 5, to reflect that.

Optimization. There is a way to make the MIPS program in Figure 2.10 run faster, which we call partial loop unrolling. This involves repeating part of the loop body outside the loop itself, thereby allowing one to write fewer statements inside the loop. The result appears as follows:

Here, we have removed one statement from the body of the loop shown in Figure 2.10 by moving the initial loop setup operations and initial test for condition to a location before the loopback point (label Loop). This allows us to remove the j Loop statement from Figure 2.10, combining it with the beq statement.

This partial unrolling of the loop contents and reordering of the loop statements results in only six statements per iteration of the loop, but there are still five statements in the loop setup (before the Loop label). As a result, we have N = 10(6) + 5 = 65 statements, instead of 75, to perform the same function as Figure 2.10. This results in a relative performance gain of 75/65 = 1.154, so the optimized code is 15.4 percent faster than the code in Figure 2.10.

2.3.4.3. Dowhile Loops. A variation of the while loop is the dowhile loop. This loop has a postcondition that is evaluated after executing the statements in the loop body, rather than the precondition of the while loop. The general form of the dowhile loop in high-level language is: 

do {...statements...} while condition

where condition is a logical predicate. On the first iteration of the loop, the statements in the body of the loop are executed regardless of whether condition is true or false. Then, condition is checked, as it is at the end of every iteration thereafter.

Example 7. Figure 2.11 shows the high-level language representation of a simple do-while statement (in the upper left quadrant of the figure), followed by the implementation in terms of go-to statement (upper right). The register assignment (lower left) references the MIPS assembly code (large box at lower right).



Figure 2.11. Implementation of a dowhile statement in terms of MIPS assembly language, with register assignments shown in the lower left-hand box - adapted from [Maf01].

Self-Exercise. (1) Repeat the analysis we gave for the while loop (Section 2.3.4.2) to determine now many instructions would be executed for A[i + m * j], for m = 10. (2) How could you use the optimization technique presented in the preceding section to make this loop more efficient? If this is not possible, show why. (A problem like this will likely be an exam question.)

2.3.5. Inequalities

In practice, algorithms and computer programs need to compare values using inequalities such as (<) and (>). In MIPS, such comparison is implemented via the set on less-than instruction, called slt or slti. The MIPS assembly instruction has the following format:

slt register1 register2 register3 ,

and implements a comparison operation that has the following functionality (in high-level pseudocode): 

       if register2 < register3 then
           register1 = 1
       else
           register1 = 0
       endif

Example 8. Suppose we want to program the following high-level code fragment in MIPS assembly language: 

       if (g < h) then goto Less ;

The following MIPS assembly code suffices:

The first statement places the value 1 in register $t0 if register $s0 < register $s1, and a zero otherwise. The second statement tests whether or not there is a nonzero value in register $t0, by comparing it with the zero value stored in the register $0. If the test for inequality fails (i.e., there is a zero in register $t0), then control is passed to the next statement. Otherwise, control is passed to the instruction in memory referenced by the label Less.

An alternate form of the slt instruction is slti (set on less-than, immediate mode), which allows comparison of register contents with a constant value that is hardcoded into the assembly language instruction. The slti instruction has the following format: 

        slti register1, register2, constant

where constant is a hardcoded constant value.

Example 9. The slti instruction is useful in loops. For example, if g is a loop index, and we want to implement the following high-level code fragment: 

        if (g >= 1) goto Loop;

then the following MIPS instructions would be employed:

Here, the first instruction says that register $t0 = 1 if g < 1, where the constant 1 is hardcoded into the instruction (hence, the use of immediate addressing). The second instruction transfers control to the label Loop if g is greater than or equal to 1.

For unsigned number representations, which we shall discuss later in this course, the sltu and sltiu instructions are employed. These function similarly to slt and slti.

Relational operators other than equals and not-equals are unsupported in MIPS assembler. Instead, the following constructs can be used to create assembly language representations of the remaining relations:

We call these pseudoinstructions because while they are not directly supported by the MIPS assembler, they can be constructed from other MIPS assembly language instructions.

2.3.6. Case and Switch Statements

The high-level language statements called case or switch select a statement or group of statements to be executed based on the value of a key variable. In Figure 2.12, the high-level code is expressed in terms of the C-language switch statement (upper left-hand box). The arrow pointing down to the if statement (lower left-hand box) shows how the switch statement is translated into a series of if statements, which we already know how to implement in MIPS assembly language (per Section 2.3.3). The assembly code is shown in the right-hand box.



Figure 2.12. Implementation of a switch statement in terms of MIPS assembly language, with register assignments shown at the top of the right-hand box - adapted from [Maf01].

2.3.7. Jump Tables

It is possible to store in memory the addresses of machine language instructions to which control is to be transferred (for example, by a conditional branch). Thus, let a jump table be comprised of registers that contain the memory addresses of machine language instructions that are referenced by labels L0 through L3. We use the MIPS instruction called jr (for jump register to implement the jump to the address contained in a given register that is referenced by the jr instruction. Figure 2.13 illustrates this process.



Figure 2.13. Implementation of a jump table in memory using MIPS assembly language, with register assignments shown at the top of the right-hand box - adapted from [Maf01].

2.3.8. Procedure Support

In order to run programs that are comprised of multiple procedures, the MIPS ISA must support memory mapping and C or C-like function definitions and encapsulation, as well as stack-based execution and some type of compilation. In this section, we discuss these concepts and how they are implemented in MIPS.

2.3.8.1. Memory Map. In order to keep the storage of data and instructions for a given program orderly, MIPS uses the memory map illustrated schematically in Figure 2.14. Here, there is a 4MB reserved space starting at hexadeciaml address 0x00000000 to the text segment, which starts at 0x00400000. The reserved space is used for system bookkeeping and other functions, while the text segment stores a program's instructions.



Figure 2.14. Layout of memory in MIPS architecture, where $gp denotes global pointer - adapted from [Maf01]. You can read about this further in Section A.5 of your textbook [Pat98].

The data segment begins at 0x10000000 and is divided into two parts. The static data segment contains objects whose size is known to the compiler and whose lifetime extends throughout the program's execution. By lifetime, we mean the interval during which a program can access data. In contrast, dynamic data is allocated by the program as it executes. For example, the C malloc function allocates memory dynamically by finding and returning a new block of memory using operating system utilities.

The program stack segment resides at the top of the address space, starting at 0x7FFFFFFF. The stack is a dynamic structure that stores values generated by different operations throughout the course of a program's execution. Since the contents of the stack are not known at compile time, the stack size varies, hence the large memory space alloted to it.

This three-part division of memory (text, data, and stack segments) has the advantage that the dynamically expandable segments (dynamic data and stack) are as far apart as possible, but are positioned to use the entire program's address space, if necessary.

2.3.8.2. Data Segment. Two instructions (lui and lw) are needed to access the data segment, as shown in Figure 2.15. To avoid repeating the lui insturction at every load and store, MIPS typically dedicates a register called $gp (global pointer) to the static data segment. This register contains address 100008000016, so load and store instructions can use their signed 16-bit offset fields to access the first 64KB of the static data segment.



Figure 2.15. Accessing an entry in the data segment, adapted from [Maf01].

Figure 2.15 illustrates the rewriting of the instruction pair 

        lui $s0, 0x1001
        lw  $v0, 0x8020($s0)

using the global pointer, as the single instruction 

        lw  $v0, 0x8020($gp)

Additionally, $gp renders more efficient the addressing of locations 1000000016 through 1001000016 than other heap locations. MIPS compiler usually stores global scalar variables in this area because these variables have fixed locations and fit better than other global data such as arrays. (The scalars are smaller and can thus be packed more efficiently into limited memory space.)

2.3.8.3. Support for C Functions and Procedures. The C language (and many other high level languages) are modularly structured, being comprised of numerous functions, procedures, or subroutines. These functions are called from the main program, and can be called by each other, leading to a transfer of control that is diagrammed with arrows in Figure 2.16.



Figure 2.16. Calling sequence in C, adapted from [Maf01].

A key implementational question pertains to the bookkeeping information that the compiler must keep track of. In the C calling sequence as implemented in MIPS, the following information is accounted for:

The procedure address includes the labels that reference the procedure, and their addresses. The return address points to the location in memory that control is transferred to after the called procedure completes. The argument registers contain the values referenced by the formal arguments of the called procedure. The return values are what is returned by the called procedure through the return statement when the procedure completes. If the called procedure is declared a void procedure, then $v0 and $v1 are empty. As discussed previously $s0 through $s7 are used to store values referenced by variables that are local to (within the scope of) the called procedure.

Because procedures are dynamic, procedure call frames (PCFs) are used to store this bookkeeping information. Typically a PCF contains arguments, save registers, and local variables. If a machine has a small number of registers, then the state S of the registers must be saved prior to calling a subordinate procedure. Otherwise, the calling procedure or program's state will be obliterated. After the called procedure completes, then the machine is restored to S, augmented by the values returned by the called procedure. The register conventions shown in Table 2.1 apply to called procedures (termed callees) as well as to the calling procedure or program.

2.3.8.4. The Stack. The stack is where the stack frames, also termed Procedure Call Frames or PCFs, are temporarily stored in memory. The stack begins at address 0xFFFFFFFF and can be expanded upward. However, 0xFFFFFFFF up to 0x7FFFFFFF is reserved space. Thus, the stack frame corresponding to the main program begins at 0x7FFFFFFF, as shown in Figure 2.17a.


(a)

(b)

Figure 2.17. (a) MIPS stack and (b) stack frames for called procedure, adapted from [Maf01].

In Figure 2.17b is shown the stack with the main program's stack frame and the called procedure (callee) frame. In this case, the callee frame ranges from address $fp to $sp (the stack pointer, which points to the furthest extent of the stack). The argument registers ($a...) and the return value registers ($v...) are stored in the callee's stack frame. Extra arguments that cannot be stored in $a0 through $a3 are stored in the calling procedure's stack frame. Additionally, memory locations that store the calling program's (caller) state are referenced by their addresses stored in the caller's stack frame (denoted by VAT in Figure 2.17b).

The following process occurs when a procedure is called:

We can better understand this sequence of operations if we analyze a simple example.

Example 10. Consider the following example of a program that calls an addition function sum(x,y):

Here, the first two add instructions put the arguments of sum into the argument registers $a0 and $a1. Then, the return address is set at 1016, the address of the instruction after the subsequent jump. The jump instruction jumps to the label sum, which is references memory address 2000. Here, the local variables x and y, whose values are stored in the argument registers $a0 and $a1, are added and the result put in the return register $v0. Then, the instruction jr (jump register) is executed to pass control to the return address ($ra = 1016, which was set in the third instruction).

Alternate Approach. The preceding process can be made more efficient by eliminating one instruction in favor of the jal (jump and link) instruction. This should actually be called the link and jump instruction, since it automatically stores the address of the next instruction in $ra, then jumps to the label specified in the instruction syntax:

jal label

Jump and link is a J-format instruction, which would be used in the preceding example to implement the following code:

Self-Exercise. In the preceding example, all other things being equal, what is the efficiency realized by substituting the jal instruction for the j instruction? Justify your answer quantitatively.

The jal instruction is also useful for nested procedures, where one procedure is called from inside another. The following code fragment is illustrative: 

       int sumSquare(int x, int y) {
         return mult(x,x) + y;
      }

This code fragment is rendered in MIPS assembler as follows:

Here, instead of using addition instructions to store values in registers, we use load and store instructions to perform very fast memory I/O to save and restore variables. The boxed instructions show how arguments are the return address are saved in a very efficient manner. The addition instructions require the ALU to be activated - load and store do not require the ALU, which is much slower than register I/O. Since we perform many I/O operations for procedure calls, mainly in saving and restoring the procedure state via the stack frame, we want to make the common case fast and use the most efficient means of handling arguments and jump addresses that we possibly can.

2.3.8.5. Stack and Recursion. The final perversion of the previous development sequence (procedures => multiple calls => nested procedures) occurs when we have recursion, where a procedure can call itself many times (in the worst case, infinitely). This causes a large number of procedure call frames to be stored on the stack. It is thus possible to run out of stack space. We call that undesireable condition stack overflow. There are several ways to avoid stack overflow, including virtual memory (paging stack contents to disk), which we will discuss later in this course. In the meantime, consider the following example.

Example 11. Recall that the factorial of a number N can be computed as

N! = N · (N-1) · (N-2) · ... · 2 · 1 .

Thus, the factorial is recursive. As a result, a routine fact(x) that computes the factorial of its integer argument x could be written as:

fact(x) = x · fact(x-1) · fact(x-2) · ... · 1 .

This implies the following C code for the factorial function: 

        main(){
           int f;
           f = fact(10);
           printf("Fact(10 = %d\n",f);
        }

        int fact(int n){
           if (n < 1)
              return(1);
           else
              return(n * fact(n-1));
        }

As a result, the stack will be loaded with stack frame for the main() routine, followed by the stack frames for fact(10), fact(9), ..., fact(1), in that order, as shown in Figure 2.18a. This is a representation of the stack when the recursion is "wound up", i.e., all the calls to fact(n) have been made. Then, the stack is "wound down" by evaluating each call to fact(n), using the stack frames pushed onto the stack when the stack was wound up. Thus, the calls to fact will be evaluated in the order fact(1), fact(2), ..., fact(10), followed by the evaluation of the remainder of the main procedure. This is done by (1) popping the stack frame for a given call off the stack, (2) evaluating the call, then (3) going back to the stack for the next stack frame. When the stack is empty, the program has been evaluated. The MIPS assembly code for this process is shown in Figure 2.18b.


(a)

(b)

Figure 2.18. (a) MIPS stack for the factorial program main shown above, and (b) corresponding assembly code, adapted from [Maf01].

Self-Exercise. The program shown in Figure 2.18b is explained in detail in Appendix A of the text [Pat98], pages A-26 through A-29. Please familiarize yourself with this example, as well as the example that computes the Takeuchi benchmark, which is discussed in detail on pages A-29 through A-32.

In summary, MIPS has several conventions that make procedure calls feasible. First, the callee can use VAT registers freely. Second, the caller can use the S-registers without having his values overwritten. Third, you can use the stack to save your data or instruction addresses, provided that you leave it the way you found it (i.e., pop off the things you pushed onto the stack after you are done using the stack). Fourth, the register conventions should be observed, to keep memory access consistent. Fifth, MIPS provides instruction support in terms of the jal and jr instructions, where jal operates on a label, and jr operates on a register (e.g., $ra).

2.4. Number Representations, Data Types and Addressing

Reading Assignments and Exercises

In this section, we discuss theoretical and practical foundations for representing numbers in digital computers, including MIPS. We then show how different types of data are represented and referenced (via addresses) in MIPS.

2.4.1. Number Representations

In Section 1, we showed how different number systems (e.g., binary, decimal, hexadecimal) could be used interchangeably to represent a wide range of integers. Computers used fixed precision number representation. This means that if a number can be represented using N binary digits, then the range of possible values for that representation is -2N-1 to 2N-1 - 1.

Because of the precision problem, the laws of continuous algebra do not always hold in computer arithmetic. We will shortly see why this is so. First, let us consider issues associated with computer representations. Note that bits can be used to represent anything - text, characters, images, colors, etc. However, N bits can only be used to represent a maximum of 2N distinct (unique) objects.

2.4.1.1. Signed Magnitude Encoding. Number representations in binary arithmetic tend to be problematic if you want to represent negative numbers and zero. For example, one can used signed magnitude encoding, which represents a number (e.g., -37) as a binary number (e.g., 1x0100101). Here the minus sign is represented by a leading 1. If a positive number is thus represented, the leading digit is zero. (Note that the leading digit is called the most significant bit or MSB.) The problem with signed magnitude representations is that there are two representations for zero, namely -0 (1x0000) and +0 (0x0000). This makes arithmetic circuits compilcated. Hence, signed magnitude encoding was abandoned early in the development of computer arithmetic.

2.4.1.2. Ones Complement Encoding. Numbers can be encoded using ones complement, which makes arithmetic circuits simpler. For example, 710 = 001112, but -710 = 110002. Thus, positive numbers have leading zeroes, while negative numbers have leading ones. Unfortunately, there are still two zero representations (0x0000 and 0x11111).

2.4.1.3. Twos Complement Encoding. An improvement over ones complement is realized by making each positive binary number x start with zero and -x = not(x) + 1. For example,

Thus, positive (negative) numbers can have infinitely many leading zeroes (ones). Twos complement numbers have some interesting properties, for example, the negation property. Let x' denote the negation of binary number x (e.g., if x = 1010, then x' = 0101). The following assertion holds:

Example 12. Consider the following conversion from the decimal number 4 to -4, then back to 4:

The steps are shown in blue, with the "trick" of adding one to the inverted result shown in red (on the left-hand side), with its result shown in red (on the right).

Complementary representations present some interesting implementational issues. If one does not differentiate between signed and unsigned numbers, comparisons can be problematic. For example, if x = 1110101 and y = 0110101, then x > y if the representation is unsigned, but x < y if the representation is signed. Thus, one must consistently use signed or unsigned number representation in a computer architecture.

Another issue is sign extension when converting from a reduced-precision representation to a higher precision representation. For example, supposed we have an eight-bit twos complement number x = (1111 1100), that we wish to convert to a 16-bit representation. Because positive (negative) twos complement numbers have an infinite number of leading zeroes (ones), we can simply view any N-digit twos complement representation as a leftward truncation of the actual (infinite-length) twos complement representation. Thus, expressing x in 16-bit format is merely a matter of filling the more significant bits with the leading bit of the low-precision form, e.g., x becomes (1111 1111 1111 1100)). This also holds for extension of leading zeroes, which is another reason that twos complement numbers are useful in computing.

2.4.2. Datatypes

As we stated in the introduction (Section 1), one of the big ideas of computer science is that data is pliable - it can be anything that the program requires it to be. In general-purpose computing or with high-level languages, data can include integers, floating point numbers, characters, strings, dates, currency information, text, objects (e.g., abstract datatypes), blobs in graphics, double precision numbers, as well as signed or unsigned number representations (as discussed in the previous section).

MIPS provides support for numeric datatypes such as integers (signed and unsigned representations) and floating point numbers, as well as strings, memory addresses (pointers), and instructions. MIPS also supports 16-bit constants (immediates), halfwords (16 bits), and bytes (8 bit).

As shown in Figure 2.19, the lb (load byte) instruction expressed as lb $s1, 4($s0) transfers data from the address contained in register $s0, with an offset of 4 bytes, to the register $s1. This can also be accomplished with the lbu (load byte unsigned) instruction, as shown in Figure 2.19.



Figure 2.19. Example of the load byte instructions, adapted from [Maf01].

Another application for which MIPS can be used is string manipulation, which helps illustrate the use of lb and sb instructions (byte I/O). The following example is illustrative.

Example 12. Suppose we want to copy string x to string y. We can use the C language routine 

        void strcpy(char x[ ], char y[ ]) {
           int i ;                        
           i = 0 ;                        # initialize loop counter
           while ( (x[i] = y[i] ) != 0)   # check for end-of-string
             i = i + 1 ;                  # increment loop counter
        }

Here, strcmp exits when x[i] and y[i] are unequal, i.e., when a difference is found in the characters of xy at a given position i. This is implemented in MIPS, as follows:

Here, the routine strcpy has three parts: (1) the prologue, which comprises the first three statements that set up the stack and initialize the $s0 register; (2) the body that contains the MIPS representation of the while loop; and (3) the epilogue that resets the address space (stack pointer) and jumps to the return address (which we assume was set prior to jumping to strcpy label).

Assume that base addresses for arrays x and y are found in argument registers $a0 and $a1, while i is in $s0. In the prologue, the stack pointer is adjusted and $s0 is saved on the stack. The register $s0 is then set to zero, and the loop begins at label L1. The address of y[i] is formed by adding offset i (in $s0) to y. Note that the offset need not be multiplied by 4, as in previous examples, because the characters in x. and y are an array of bytes, not 32-bit words. To get the character in y[i] from memory to register, we use the lb instruction, which puts the character into $t2.

The next step is to transfer the character from $t2 to memory. To do this, we first put the address of x[i] in $t3, then use sb (store byte) instruction to transfer the character in $t2 to that address. If the character is a zero (end-of-string character in C), then we exit the loop and go to label L2. Otherwise, the loop index is incremented with the addi instruction, and we return to L1. In the epilogue, the stack pointer and $s0 are reset, and control is transferred to the return address.

In actual C-language string manipulations, pointers are used, as discussed in Section 2.6. This avoids the overhead associated with loop index manipulation.

2.4.3. Addressing

MIPS has several types of addressing, including immediate mode for constant-valued operands. As stated in Section 2.2.3.1, the common case is that small constants are used frequently. Thus, in order to make the execution of operations with small constants fast, we (1) put the constants in memory then (2) load them into registers. A second type of addressing puts constants directly into the assembly language instruction (e.g., hardcoded constants). We address these constants in immediate mode, for example, the following add-immediate instruction:

Immediate mode can be useful for purposes other than arithmetic. For example, suppose we want to load a 32-bit word into a register, but MIPS supports only 16-bit constants. The trick here is to first load the higher-order bits using the load upper immediate instruction 

        lui $t0, 10101010101010101010

which loads the constant (second operand) into the upper half (more significant 16 bits) of $t0. We then load the remainder of the lower order bits using the or-immediate instruction: 

        ori $t0, $t0, 10101010101010101010

which works as shown below:

MIPS has several additional addressing modes, including data and instruction modes. Data addressing features register addressing (the fastest and shortest mode), base addressing (for operands in memory, e.g., lw $t0 20($t1), and immediate addressing that hardcodes a constant directly into an instruction. We have already studied each of these modes.

Instruction addressing modes include PC-relative addressing (for branches) and pseudodirect addressing (for jumps). The term PC means program counter, which is a special-purpose address register that points to a given instruction in the instruction sequencer.

In PC-relative addressing, the address is the PC + C · 4, where C denotes a constant hardcoded into a branch instruction. This allows the program address space to be (in principle) as large as 232 instructions. If we simply used PC, only 216 instructions would be allowed (16-bit address space), which is far too small for modern programs.

In pseudodirect addressing, the address is PC[31:28] (upper six bits of the PC address) concatenated with the 28-bit word represented by the 26 bits of address in the jump instruction. This is useful for long jumps (not the common case), and can be inserted by the MIPS assembler, as follows. In practice, the assembler performs this insertion of a large jump (to a far target address) by converting a beq branch to a bne branch, as shown below.

Here, the current PC is outside the memory segment in which local activity occurs (the shaded region in the preceding illustration). The 26-bit field in the jump instruction is also a word address, i.e., it represents a 28-bit byte address. To make up the remaining four bits, MIPS uses the upper four bits of the PC. As a result, the loader and linker must be careful to avoid placing jumps across an address boundary of a 256MB segment. Otherwise, the jump must be replaced by a jump register instruction, where the full 32-bit address must be loaded into the register using an immediate-mode instruction like that shown in the ori example, above.

2.5. MIPS Programs

Reading Assignments and Exercises

MIPS supports translation of high-level languages (HLL) such as C to assembly language, then to object code and executable code. In this section, we examine this process, shown schematically in Figure 2.20.


Figure 2.20. Example of MIPS compilation sequence, adapted from [Maf01].

Here, the C source file foo.c is compiled using the C compiler (Unix command cc), to yield an assembly language program foo.s. This program is input to the MIPS assembler (Unix command as), producing an object (machine language) module foo.o. The linker (Unix command ld) links a library lib.o with the object module to produce the executable file a.out. When the executable is invoked (via the Unix command a.out), the loader puts the executable code into memory, and the program is run.

The assembler, which is of concern to this course, performs the following tasks:

  1. Reads and executes directives for special treatment of input (per Section 2.5.1)

  2. Replaces pseudoinstructions (shown below in the left-hand column) with blocks of instructions supported by MIPS (shown below to the right of the pseudoinstructions), for example:

  3. Produces machine language file, as discussed in Section 2.5.2; and

  4. Creates an object module with filename ending in ".o", whose structure is overviewed in Section 2.5.3.

We next consider assembler directives, which are somewhat like preprocessor commands in C.

2.5.1. Assembler Directives

The MIPS assembler supports the following directives, which do not produce machine language code, but merely control the functions of the assembler:

Another assembler feature is absolute addressing, which is described as follows. Absolute addressing supports relocation editing by implementing load/store operations to variables in static memory, conditional branches, jump instructions, and direct references to data, as shown below:

In some cases, these references cannot be determined at assemble time (when the assembler translates MIPS code to machine language), so temporary data structures are created, as described in the following section.

2.5.2. Production of Machine Language

In the simplest case, machine language instructions can be directly produced from MIPS assembly code. Here, the basic information needed to translate the assembly instruction to one or more machine language instructions is already within the instruction. Arithmetic, logical, and shift instructions are in this category.

With conditional branches, some delay is encountered, since pseudoinstructions (not directly supported by the MIPS assembler) have to be translated first into their assembly language equivalents (instructions directly supported by MIPS). After all the pseudo instructions have been translated, it is possible for the assembler to make a second pass, where the machine language instructions are counted up, and the branch target addresses (where the branch instructions transfer control to) can be calculated. The PC-relative addressing mode is useful for this step of machine language production.

Direct (absolute) addressing presents a problem, due to jumps (j and jal instructions), as well as direct (absolute) references to data. These cannot be determined at this step of the assembly process, so we need to create two tables: the symbol table and relocation table.

The symbol table contains a list of object s in the assembly language program that may be used by other files. This includes labels, for function calling, and data (e.g., anything in the data directive or variables that are to be accessedacrossed files. On the first pass, the assembler records label-address pairs. On the second pass, machine code is produced. Thus, it is possible to jump to a subsequent label without declaring it first.

In contrast, the relocation table is a list of objects for which the assembled program needs addresses. This includes any label jumped to (j or jal instruction), whether internal or external (including library files). Also, the relocation table contains any piece of data specified within the program.

2.5.3. Structure and Creation of Object Module

The object module contains the following information:

2.5.4. Linker

The linker combines object (.o) files into an executable file. This enables separate (independent) compilation of files. However, only the modified files are typically recompiled. For example, Windows NT source code has over 30 million lines of code, so we want to perform incremental compilation on this large corpus of code, rather than attempting to compile it all at once.

The linker also edits the links in the jal (jump-and-link) instructions, substituting addresses where appropriate. This is why the linker used to be called the link editor.

The linker performs the following steps:

There are four types of references that need to be resolved, which are:

The linker assumes the first word of the first text segment is at 0x00000000. Since the linker knows the length and ordering of each text and data segment, the linker can calculate the address of each internal or external jump target as well as the address of each piece of data being referenced.

2.5.5. Loader

The linker produces an executable file that is stored on disk. The loader puts the executable code in memory and starts it running. As a result, the loader is often thought of as a part of the operating system. The loader performs the following functions:

  1. Read header to determine the size and the text and data segments

  2. Create new address space for the program that is large enough to hold the text and data segments, and also the stack

  3. Copy instructions and data from executable file memory

  4. Initialize the machine registers, for example, $sp points to the first free stack location

  5. Jump to the initial routine that copies the program arguments from the stack to the registers, then sets the PC

  6. When the main routine returns, the start-up routine terminates the program execution with a system call.

Thus, the loader can be thought of as the runtime module.

In summary, the compiler converts a single HLL file into an assembly language file. The assembler translates pseudoinstructions, converts what instructions it can directly to machine language, and creates a checklist for the linker called the relocation table. This changes each source file into an object file. The linker combines several object files (including libraries), and resolves absolute addresses. The loader loads the executable produced by the linker into memory and begins program execution.

2.6. Pointers and Arrays

Reading Assignments and Exercises

In this section, we discuss in greater detail the issues surrounding pointers (addresses) and contiguous regions of memory that store values in arrays (as discussed in Section 2.6.1). Salient implementational issues include argument passing as well as the lifetime and scope of storage (Section 2.6.2). Uses of pointers include pointer arithmetic (Section 2.6.3) and the use of pointers with arrays (Section 2.6.4).

2.6.1. Basic Pointer Concepts

Definition. A pointer is a variable that contains the address of another variable.

In practice, a pointer can be thought of as the HLL equivalent of a machine language memory address. We use pointers to express a program's functionality more compactly and efficiently, and to perform memory operations that cannot be done another way. Unfortunately, pointer mis-use comprises the largest amount of bugs in a typical program, with the following two errors predominating:

  1. Dangling Reference - when a pointer points to a memory location that has been prematurely freed

  2. Memory Leaks - when a memory location has been freed too late, or not freed at all, and a pointer still should reference it.

As a result of these defects, a program must be restarted frequently to avoid accumulation of dangling references or leaks.

Let us consider several example of pointer use in the C language.

Suppose a variable v has value 100, and is located in memory at address 0x10000000. The unary operator (&) gives the memory address of v, for example: p = &v; while the (*) operator gives the value that pointer p points to, for example: value = *p. We call the (*) operation dereferencing, and it is important in assembler, as shown below:

Thus, the (*) operator, used to the right (left) of the equals sign, can implement a load (store) operation.

Example 13. Assume that the variable c is an integer, has value 100, and resides in memory at address 0x10000000. Further assume that the pointer p is stored in register $a0, and that the variable x is stored in register $s0. The following code fragment is illustrative of dereferencing. the numbered code is C language, with assembly instructions listed below:

The first item puts the address of c in p. The second item dereferences p to put the value stored at that address in x, which is a synonym for $s0. Finally, the memory location whose address is in p receives the value 200. Note that the addi (add immediate) operator is used to put the value 200 in register $t0, then the contents of $t0 are stored in the location pointed to by $a0 (which contains the value of p).

We already know about memory leaks and dangling pointers. This concept of data persistence leads us to ask how long pointers last within a program. We discuss this in the following section.

2.6.2. Storage Lifetime and Scope

There are three types of pointer allocation that affect the storage lifetime and scope of the pointer:

We will next examine how we can manipulate these different types of pointers to achieve different addressing modes.

2.6.3. Pointer Arithmetic

Various types of arithmetic operations can be performed on pointers. For example, addresses can be incremented and decremented, assigned, dereferenced, etc. The following example is illustrative of memory operations, where the array z contains various values referenced by pointers:

Note that there are two instances of mistakes using pointers. The first involves hardcoding a direct address into a C-like program - a very bad idea, for two reasons: (1) one can reference a protected part of memory where system resources reside, or (2) future operating system or compiler revisions might not support such a modification. The second error, which is an illegal operation, involves trying to make the entire array z point to the scalar variable y, using the statement z = &y.

Example 14. As a further illustration of pointer usage, consider the following C code:

which is translated into the following assembly language instructions:

Note that the argument in $a0 dereferences the actual argument variable (a string s), so that the pointer p points to the characters in the argument. The addi instruction is used to increment p so it points to the next character in the string. In both cases, the lbu (load byte unsigned) instruction is used to effect the dereferencing.

After the loop completes, the length of the string is equal to the different p - s. This is yet another example of pointers can be used both as addresses and as counters. This makes the assembly code much more compact, and thus produces fewer instructions.

When using pointers in an argument list, we implement the latter of the follwoing two argument passing modes:

In practice, it is easier to pass single word variables by value, since this avoids the overhead of pointer manipulation.

2.6.4. Use of Pointers in Array Manipulation

Suppose we have an array (e.g., a[100]) in the argument list. This can be passed in two ways. The Pascal language uses call-by-value (e.g., copies the entire 100 words of a onto the stack). This is prohibitively costly for large arrays. In contrast, C (call-by-reference) passes a pointer (one word long) to the array a, with the pointer being stored in a register for fast manipulation.

There are four versions of array manipulation for a binary arithmetic operation (e.g., adding arrays a[100] + b[100] and putting the result in c[100]).

  1. Result array is passed to the function or procedure.

  2. The result is put in a local array on the stack, and a pointer to the local array is passed to the function or procedure.

  3. The result array is allocated on the heap.

  4. The result array is declared static.

We discuss each of these techniques with an example, as follows. Each example assumes that we have an array addition routine called sumarray.

Example 15 (Array passed to Function). Given the following C code: 

        int a[100],b[100],c[100];
         sumarray(a, b, c);

the meaning of this C calling convention is 

         sumarray(&a[0], &b[0], &c[0]);

If we want to use assembly language to pass pointers that reference arrays, then we need to compute the address size (.e.g, a 100-element array requires 400 bytes of storage in MIPS). This is done as follows:

Note that the addi instruction is used to set the base addresses, with a[0] starting at $gp. Then, the jal instruction is used to invoke sumarray, as discussed previously. The C code and compiled assembly code for the function sumarray looks like this:

The second method is to put the result array on the stack as a local array, then return the pointer to that array to the function or procedure, as follows.

Example 16 (Array Pointer passed to Function). In the following code, notice how the prologue portion of the assembly code uses the addi instruction to allocate space for the result array c, set the pointer, and pass it to $v0 (the first result register):

The loop is straightforward, and begins with a limits check that branches to the exit point if the loop index (in register $a0) is exceeded. Next, the operands a[i] and b[i] are respectively loaded into registers $t1 and $t2, the addition operation is performed, and the result is stored in memory location referenced by $t3 with zero offset. The input operand pointers and result pointer are reset, then the jump instruction transfers control to the loopback point.

The next two techniques are not used very often. Placing the array on the heap renders the array information not reused unless freed. This leads to memory leaks. Using static arrays is memory-consumptive, but tends to be employed in C libraries.

Example 17 (Result Allocated on Heap). Given the following C code:

the compiled version is as follows:

Here, the heap allocation is accomplished by the call jal malloc, which is necessarily bracketed by the saving and restoring of the arguments. Note the many additional lines of code that are required beyond those shown in Example 16. As a result, memory allocation looks like this:

The final example uses static memory for array storage.

Example 18 (Static Memory). Given the following source code fragment:

Note that the static directive causes the array to be in static memory, as shown below:

As a result, the array c will be changed next time sumarray is invoked. This method is typically used in C libraries, and is very expensive from the viewpoint of memory usage.

This concludes our overview of ISA, instruction set, and addressing issues. We next discuss integer and floating point arithmetic.

References

[Maf01] Mafla, E. Course Notes, CDA3101, at URL http://www.cise.ufl.edu/~emafla/ (as-of 11 Apr 2001).

[Pat98] Patterson, D.A. and J.L. Hennesey. Computer Organization and Design: The Hardware/Software Interface, Second Edition, San Francisco, CA: Morgan Kaufman (1998).